- #1
pmahesh107
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A sample of silver with a mass of 63.3 g is heated to a temperature of 384.4 K and placed in a container of water at 290.0 K. The final temperature of the silver and water is 292.4 K. Assuming no heat loss, what mass of water was in the container? The specific heat of water is 4.184 J/(g C) and of silver, 0.24 J/(g C).
I don't understand what to do for this problem. When I set it up, I end up having 2 unkowns for water. Can someone please show me how to set this up? thanks
i tried it a number of different ways but the only way i could get mass was
4.184 = x/ 181.15 <- converted to celsius from Kelvin
4.184/181.15 = x
.0231 g = x
I don't understand what to do for this problem. When I set it up, I end up having 2 unkowns for water. Can someone please show me how to set this up? thanks
i tried it a number of different ways but the only way i could get mass was
4.184 = x/ 181.15 <- converted to celsius from Kelvin
4.184/181.15 = x
.0231 g = x
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