Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Measuring impedance of a coil

  1. Nov 18, 2014 #1
    Why don't we just connect a sine wave generator in series with a DMM and the coil, set the amplitude Δv0 to a given value on a scope, measure the RMS current I on the DMM and use Z = 0.707Δv0/I?
     
  2. jcsd
  3. Nov 18, 2014 #2
    Not that simple. The reactance of the coil is frequency dependent (jωL). Less current will flow as frequency goes up. There is also the resistive part of the coil which could affect results.
     
  4. Nov 18, 2014 #3
    Yes, I know that Z depends on f, L and the resistance R of the coil. But you could measure Z by the method I described above and then find L (let's say) from the measured values of f and R. But nobody seems to do it like that.
     
  5. Nov 19, 2014 #4

    meBigGuy

    User Avatar
    Gold Member

    Of course that only works if you care about Z in a frequency range that your DMM can deal with, and you don't care about DMM resistance or lead inductance. The DMM resistance could be more than your inductor. You should try it in the lab with a few inductors and see what the practical issues really are.

    Easier to stick an R in series and measure with the scope.
     
  6. Nov 19, 2014 #5
    In the lab I used a 2.5 mH inductor (measured with a LCR bridge) having a 20 Ω resistance. Working in the frequency range of the DMM, the impedance I obtained from Z = 0.707Δv0/I was always significantly higher than the one I calculated from f, L and R. Could it be due to the fact that R is higher than 20 Ω when current flows, either because the coil wire is not ohmic or because of the skin effect ?
     
  7. Nov 19, 2014 #6
    Do you want to measure coil inductivity or just coil impedance at some frequency? There's big difference. Coil impendance (at low enough frequencies) you can always measure as IZ I=Vrms/Irms if current and voltage waveforms are clear sine waves. But, if you measure ferromagnetic core coil's Z by simple V-I method, you may run into problems due to nonlinear features of magnetizing current. And to accurately determine inductivity (L) of nonferromagnetic coil by this method you need to know angluar shift between current and voltage wave or resisistance Rω=f(ω) of coil wire (phase shift will not be exactly 90°due to loses). Only if skin and proximity effects can be neglected (ie. low ω) you have Rω= RDC. Therefore, it is recommended you measure real power to the coil during measurement. Measured inductivity is then:
    latex?L_{x}%3D\frac{\sqrt{%28V_{rms}\cdot%20I_{rms}%29^{2}-P^{2}}}{\omega%20\cdot%20I_{rms}^{2}}.gif
     
  8. Nov 19, 2014 #7
    Thank you zoki85. So if I understand well the IZ I=Vrms/Irms method will only allow me to determine L accurately for a nonferromagnetic coil and low frequencies.

    Now, would the IZ I=Vrms/Irms method allow me to determine the capacitance of a capacitor from Z = 1/2πfC, using the frequency I like ?
     
  9. Nov 19, 2014 #8
    If you can neglect loses, yes. Otherwise, you need to now Rω or φ or P. There could be also other issues like parasitic capacities if you go too high with frequency.
    Same kind of considerations holds for capacitor msms.
     
  10. Nov 19, 2014 #9
    Thank you! How can you measure P?

    One last question: with the coil connected directly to the generator, I noticed that for high frequencies a DMM measured a RMS voltage that was less than the amplitude (as measured on the scope) divided by √2. Do you have an explanation for that?
     
  11. Nov 19, 2014 #10
    Most likely, such frequency is too high for yor DMM to be accurate enough. Trust your scope.
     
  12. Nov 19, 2014 #11
    Aim into a graduated quart/liter container. :w
     
  13. Nov 20, 2014 #12
    I see I didn't answer power msm question. If you arrived at conclusion power factor isn't negligible, especially at higher frequencies, here's what you can do. Since you already have o-scope you can use it to simultaneously capture voltage and current sinusoids through the inductor. See this video how current probe is used for this. Then you can find angle shift φ between voltage and current. And calculate P=Vrms⋅Irms⋅cos φ
     
  14. Nov 20, 2014 #13

    sophiecentaur

    User Avatar
    Science Advisor
    Gold Member

    If you have a variable frequency source and a meter or scope (plus a few odd, cheap components) then you can find the inductance of a coil be resonating it with a known parallel capacitor. In the days before posh readily available RF equipment, the Q Meter technique was used to find component values. That wiki link and others could help you make do without an expensive Impedance Bridge.
    It all depends upon the accuracy you require, though.
     
  15. Nov 20, 2014 #14
    Or, he could make Hay's Bridge , with relatively small budget
     
  16. Nov 20, 2014 #15
    In antiquity, a high input impedance transformer would be used in place of the meter and the secondary of the transformer would then drive headphones. The operator would then sweep around in the audible range looking for a null in the tone. Very crude, but sounds like fun to build.
     
  17. Nov 20, 2014 #16

    meBigGuy

    User Avatar
    Gold Member

    Sweep the frequency lower and see what happens. Put another way, measure the frequency response of your meter.
     
  18. Nov 20, 2014 #17
    With a true-RMS meter, you usually get a good response to 10kHz. Some of the old Fluke handhelds could even go to 100kHz - if calibrated properly. Cheap hobby meters are random. Many don't have a true-RMS function to save cost and those that do may have a poor frequency response.

    In any case, if you use a bridge, you would be more interested in the null than the accuracy of the meter.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Measuring impedance of a coil
  1. Coil Impedance (Replies: 2)

  2. Impedance Of Coil (Replies: 13)

  3. High Impedance Coils (Replies: 2)

Loading...