------------------------------------------------------------quark said:Are you sure about the question?
mechanical advantage = load/effortscientist said:The book gives an answer of 6.54! Do you have an explanation for the book's answer?
-------------------------------------------------------------------------HallsofIvy said:This is not at all what you originally posted!
However, the load divided by the effort is indeed 6.54! As SpaceTiger said, convert the load to Newtons. Once again, the distances given are irrelevant.
Your answer is right, but you seem to be confusing the definition of kg and kN. They're not the same thing. In fact, kg is a unit of mass and kN is a unit of force. They both have "k", which is short for "kilo", which is itself a prefix to indicate 1000. Since "g" is short for grams and "N" is short for Newtons, the kg and kN are 1000 grams and 1000 Newtons, respectively.scientist said:2000kg x 9.81N
= --------------
3000kg = 3kN
As SpaceTiger stated, mechanical advantage is just load/effort. Distances don't enter into it. If the actual effort force is used in the calculation, friction effects are included.quark said:BTW, mechanical advantage can also be calculated by distances, theoretically. Both should give you same result theoretically. But in real life, resistance and friction come into picture and that is why we base it on forces.