- #1
physics phan
- 5
- 0
ok,
heres the prob:
A 21.0 kg cannon ball is fired from a cannon with a muzzle speed of 1100 m/s at an angle of 37.3° with the horizontal. A second ball is fired at an angle of 90.0°. Use the law of conservation of mechanical energy to find
(b) the total mechanical energy at the maximum height for each ball. Let y = 0 at the cannon.
in (a), i had to find the height for each ball, which i did using ( mv^2/2 ) - mgh = 0
i found the first ball to be 2.27e4 m/s (using 1100sin37.3)
and the second ball to be 6.17e4
now i can find the mech energy
do you use ( mv^2/2 ) + mgh = Mech E
(i simplified changed in PE and changed in KE in the above equation)
and then add the two Mech Energies?
heres the prob:
A 21.0 kg cannon ball is fired from a cannon with a muzzle speed of 1100 m/s at an angle of 37.3° with the horizontal. A second ball is fired at an angle of 90.0°. Use the law of conservation of mechanical energy to find
(b) the total mechanical energy at the maximum height for each ball. Let y = 0 at the cannon.
in (a), i had to find the height for each ball, which i did using ( mv^2/2 ) - mgh = 0
i found the first ball to be 2.27e4 m/s (using 1100sin37.3)
and the second ball to be 6.17e4
now i can find the mech energy
do you use ( mv^2/2 ) + mgh = Mech E
(i simplified changed in PE and changed in KE in the above equation)
and then add the two Mech Energies?