(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 1.50 kg snowball is fired from a cliff 12.5 m high with an initial velocity of 14.0 m/s, directed 41.0° BELOW the horizontal. Using energy techniques ONLY, find the speed of the snowball as it reaches the ground below the cliff.

2. Relevant equations

(1/2)mv^2+mgy=(1/2)mv^2+mgy

Kb+Ub=Kt+Ut

3. The attempt at a solution

I am not sure how to use the angle provided with either of these equations. Is there another equation that I could use?

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# Homework Help: Mechanical Energy

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