Mechanical Q: Find Air Resistance Force from .750kg Proj. at 18.0m/s

[dbtarz]

A projectile has a mass of .750kg and is shot straight up with an initial velocity of 18.0m/s. If the projectile rises to a max height of 11.8m, determine the magnitude of the average force due to air resistance. Can anyone help me with this?

 

[Kurdt]

What have you tried so far?

 

[ogb p]

I can help you with this problem. To find the air resistance force, we first need to understand that air resistance is a type of frictional force that opposes the motion of an object through the air. It is caused by the collision of air molecules with the surface of the object.

To determine the magnitude of the average force due to air resistance, we can use the equation F = ma, where F is the force, m is the mass of the object, and a is the acceleration.

In this case, the mass of the projectile is 0.750kg and the initial velocity is 18.0m/s. We also know that the projectile rises to a maximum height of 11.8m, which means that it has gone through a displacement of 11.8m.

Using the equation for average acceleration, a = (vf - vi)/t, we can find the average acceleration of the projectile. The final velocity, vf, is 0m/s at the highest point, and the initial velocity, vi, is 18.0m/s. The time, t, can be found using the equation for displacement, s = vi*t + 1/2*a*t^2. Plugging in the known values, we get t = 2.04s.

Now, we can plug in the values for mass, acceleration, and time into the equation F = ma to find the force due to air resistance. F = (0.750kg)(-8.82m/s^2) = -6.61N.

Therefore, the magnitude of the average force due to air resistance is 6.61N. It is important to note that this is an average force and the actual force due to air resistance may vary during the projectile's motion.