• Support PF! Buy your school textbooks, materials and every day products Here!

Mechanics free response

  • Thread starter dbb2112
  • Start date
  • #1
39
0

Homework Statement



A 100 kg box is being pulled along the x axis by a student. The box slides along the a rough surface and its position x varies accoring to the equation x=.5tcubed +2t, where x is in meters and t is in seconds.

a. Determine the speed of the box at t=0
b. Determine the following as functions of time t.
i. The kinetic energy of the box
ii. the net force acting on the box
iii. The power being delivered to the box.
c. Calculate the net workdone on the box in interval t=0 t t=2
d. Indicate below wheter the work done on the box by the student in the interval t=0 to t=2 wold e greater than, less than or eequal to the answer in part c.

Homework Equations





The Attempt at a Solution

 

Answers and Replies

  • #2
LowlyPion
Homework Helper
3,090
4

Homework Statement



A 100 kg box is being pulled along the x axis by a student. The box slides along the a rough surface and its position x varies accoring to the equation x=.5tcubed +2t, where x is in meters and t is in seconds.

a. Determine the speed of the box at t=0
b. Determine the following as functions of time t.
i. The kinetic energy of the box
ii. the net force acting on the box
iii. The power being delivered to the box.
c. Calculate the net workdone on the box in interval t=0 t t=2
d. Indicate below wheter the work done on the box by the student in the interval t=0 to t=2 wold e greater than, less than or eequal to the answer in part c.
How would you think to approach the problem?

You have a displacement/time graph ... so how do you read velocity?
 
  • #3
39
0
I dont really know how to approach the probelm or how i read velocity
 
  • #5
39
0
before i go there this is just guessing but would i take the derivitive of the equation to find the velocity?
 
  • #6
LowlyPion
Homework Helper
3,090
4
before i go there this is just guessing but would i take the derivitive of the equation to find the velocity?
Since that's what velocity is - the rate of change of position wrt time - then yes that's what you will need to be doing.
 
  • #7
39
0
ok, so at t=0 the velocity would be 2m/s.
It then asks to Determine the following as functions of time t. I do not understand what that means.
 
  • #8
LowlyPion
Homework Helper
3,090
4
i. The kinetic energy of the box
ii. the net force acting on the box
iii. The power being delivered to the box.
You have the velocity function.
You will need the acceleration function too.

KE - 1/2*m*v2 = 1/2*m*vt2

F = m*a

P = w*/t = F*d/t = Ft*vt

Basically you are using these functions in place of the usual functions you might employ in determining more traditional uniform gravitational kinematics.
 
  • #9
39
0
i do not really understand what finding those as functions of time means still. But i am assuming that i should just plug in the velocity i found for kinetic energy and mass they already give you to obtain the answer of 200J. And then derive the velocity again to get the acceleration of 3t? that is where I kind of get lost.
 
  • #10
LowlyPion
Homework Helper
3,090
4
i do not really understand what finding those as functions of time means still. But i am assuming that i should just plug in the velocity i found for kinetic energy and mass they already give you to obtain the answer of 200J. And then derive the velocity again to get the acceleration of 3t? that is where I kind of get lost.
In b) they are asking you for these things as functions of time. (Remember a is the derivative of v and equals 3*t, which is what you apparently have determined.)

In c) you need to integrate the product of F and X from t=0 to t=2.
 
  • #11
39
0
so with the acceleration being 3t would i sub anything in there or just multiply 3 by the mass.
 
  • #12
LowlyPion
Homework Helper
3,090
4
so with the acceleration being 3t would i sub anything in there or just multiply 3 by the mass.
No. Wherever you need to know a is where you would sub in 3*t, just as for velocity wherever you have v you sub in (3*t2/2 +2) wherever you have v.

These variables are functions of time. And the equations in b they are asking for are in terms of these.
 
  • #13
39
0
O ok so the force woudl be 300t.
 
  • #14
39
0
and for the next part, i would integrate 300t *.5tcubed+ 300t*2t?
 
  • #15
LowlyPion
Homework Helper
3,090
4
and for the next part, i would integrate 300t *.5tcubed+ 300t*2t?
That looks correct. It would be the definite integral over the time given.
 
  • #16
39
0
the only problem now is im not really sure how to do that.
 
  • #17
39
0
would it be 30t^5+300t^3? and then just plug in the times they give me?
 
  • #18
LowlyPion
Homework Helper
3,090
4
would it be 30t^5+300t^3? and then just plug in the times they give me?
It's 1/3 of 600 isn't it?
 
  • #19
39
0
o yes so it would be 30t^5+200t^3 but after that im not too sure what to do would i plug in 0 and then plug in 2
 
  • #20
39
0
could you tell me why we integrated there also?
 
  • #21
LowlyPion
Homework Helper
3,090
4
could you tell me why we integrated there also?
That comes from the definition of Work, being the integral of the product of Force in the direction of displacement and displacement.

Since they are both functions of time and you are required to identify the amount of work over that time then you need to integrate over the time to get the correct summation of all the incremental Δ FxD's

See also:
http://en.wikipedia.org/wiki/Mechanical_work#Force_and_displacement
 
  • #22
39
0
im still not grasping it, could you demonstrate what you mean please?
 
  • #23
LowlyPion
Homework Helper
3,090
4
im still not grasping it, could you demonstrate what you mean please?
Read the Wikipedia link.
 
  • #24
39
0
instead of integrating, could i just find both kinetic energies and subtract them?
 
  • #25
LowlyPion
Homework Helper
3,090
4
instead of integrating, could i just find both kinetic energies and subtract them?
Does that yield the same answer?
 

Related Threads on Mechanics free response

  • Last Post
Replies
20
Views
2K
  • Last Post
Replies
3
Views
4K
Replies
1
Views
6K
  • Last Post
Replies
3
Views
4K
  • Last Post
Replies
4
Views
1K
  • Last Post
3
Replies
59
Views
7K
  • Last Post
Replies
8
Views
2K
Replies
2
Views
1K
Replies
0
Views
2K
Replies
1
Views
5K
Top