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Mechanics Projectile question

  1. Dec 13, 2009 #1
    1. The problem statement, all variables and given/known data
    Shells are fired from a gun at 210 m/s. What is the maximum range of the shells on horizontal ground?


    2. Relevant equations

    Suvat equations?

    3. The attempt at a solution
    x=210cos(theta)t
    y=210sin(theta)t - 4.9t^2
    Not sure what to do after that.
    Help would be appreciated.
     
  2. jcsd
  3. Dec 13, 2009 #2

    tiny-tim

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    Hi pianogirl! :smile:

    (have a theta: θ and try using the X2 tag just above the Reply box :wink:)
    Hint: put y = 0. :wink:
     
  4. Dec 13, 2009 #3
    There is a more direct way to get time IMO than your eqn.

    Consider only the ascent phase.

    What happens when we reach the peak of flight to component of the velocity?

    Doing so will give you an expression where t=(210 Cos(theta))/g

    The descent will take exactly as long so the total time is 2t.

    Now substitute for this in your above eqn. You should get something times sin(theta)cos(theta)

    There is a trig identity: sin (2theta)= 2 sin(theta) cos (theta)

    Simplify your eqn using this. By considering what angle sin is at its maximum should be the answer.

    EDIT: sorry didn't see your post Tiny-Tim
     
  5. Dec 13, 2009 #4
    But I still have two unknowns....? The range and the angle.... or did I do something wrong?
     
  6. Dec 13, 2009 #5

    tiny-tim

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    But you have two equations, so that's ok :smile:

    EDIT: he he … beat denverdoc again! :biggrin:
     
    Last edited: Dec 13, 2009
  7. Dec 13, 2009 #6
    Nope you should have two unknowns, but ask yourself what angle will make y maximal?

    In other words sin (a) = max at 90 degrees so sin(2a)= max at what angle?
     
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