A block of mass 3 kg is on a rough inclined plane at 30 degree to the horizontal. The coefficient of friction is 0.2 and a force of 10 N acts upward parallel to the plane. Find the friction? The answer to the question is 5N my work Normal reaction= 30 cos 30 Using F = u R (0.2 x 30 cos 30 )= 5.20 N I am not obtaining the answer, and i don't even know whether the method is correct or not as i have not consider the 10 N. Please need help to attempt the question....!!!!!!