Mechanics question

  • #1
Pseudo Statistic
391
6
This was one of my homework assignments...
I wanted to know if my steps taken are correct.
Thanks for any feedback.

A ball rols down a ramp and travels a distance of 3.00 m in 2.05 seconds. Find (a) what is the ball's acceleration? (b) what is the ball's final speed at the bottom of the ramp? And (c) what is the ball's average speed going down the ramp?
(a) I thought I'd use the formula a = s/t^2 where s = distance, 3m, and t = time, 2.05s.
(b) I thought I'd multiply what I've gotten for acceleration by 2.05s.... or is this a conceptual thing where it's assumably 0? I don't know.....
(c) Average speed I'm guessing is the same as (b).
 

Answers and Replies

  • #2
mukundpa
Homework Helper
524
3
s = (1/2)at^2 not at^2


average speed is (u + V)/2
 
  • #3
Pseudo Statistic
391
6
mukundpa said:
s = (1/2)at^2 not at^2


average speed is (u + V)/2
Oh, OK...
I get the 0.5at^2 part, but isn't average speed total displacement over total time rather than the arithmetic mean of the 2 velocities? :\
 
  • #4
mukundpa
Homework Helper
524
3
yes, if the acceleration is constant both will give the same result.
 

Suggested for: Mechanics question

Replies
7
Views
370
Replies
14
Views
190
  • Last Post
Replies
1
Views
277
  • Last Post
Replies
21
Views
467
Replies
3
Views
328
  • Last Post
Replies
4
Views
597
Replies
9
Views
395
Replies
2
Views
565
Top