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[Mechanics] Tension in bungee jumping
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[QUOTE="sushichan, post: 5453245, member: 542740"] [h2]Homework Statement [/h2] A bungee jumper of mass 60kg jumps from a bridge 24 m above the surface of the water. The rope is 12 m long and is assumed to obey Hooke's law. What should the spring constant of the rope be if the woman is to just reach the water? [h2]Homework Equations[/h2] Ep=mgh E=1/2 kx^2 [h2]The Attempt at a Solution[/h2] Energy conservation? I'm definitely doing something wrong here and not understanding something but I don't know what. mgh = ½kx^2 (60)(10)(12) = ½k(12)^2 [I put the length of the unstretched part of the rope as my [I]h[/I] value and [I]x[/I] as the extension, which is 24-12=12] k= 100 Nm^-1 [This is the answer I got] But the answer is k=200 Nm^-2 [/QUOTE]
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[Mechanics] Tension in bungee jumping
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