- #1
Nash78
- 20
- 0
A full bridge rectifier for 2A, 2000vdc is required.
It is used for a capacitor charging circuit.
A full bridge rectifier consists of 4 diodes in theory.
But due to physical size limitations that i can install this item.
Diodes that are above 3kV does not fit my sizes, so i have another option.
What i know is, diodes can be put in series to increase the voltage.
So i want to put 3 diodes, namely BY255 in series, to form the single diode.
Reason? Cheap, reliable, axial type
It is rated 3A, 1300V. So 3 in series would give me 3900V, a good safety factor.
So my final step is, how to calculate the shunt resistance per BY255?
Online searches tell me to take the Rated Voltage of the diode x 500V
Which in my case would be 650kohms...
I cannot verify that is a good value with my current knowledge and experience.
Anyone can direct me to any source of writeups so i can understand more on how this value of 500V came about?
Thanks,
Nash78
It is used for a capacitor charging circuit.
A full bridge rectifier consists of 4 diodes in theory.
But due to physical size limitations that i can install this item.
Diodes that are above 3kV does not fit my sizes, so i have another option.
What i know is, diodes can be put in series to increase the voltage.
So i want to put 3 diodes, namely BY255 in series, to form the single diode.
Reason? Cheap, reliable, axial type
It is rated 3A, 1300V. So 3 in series would give me 3900V, a good safety factor.
So my final step is, how to calculate the shunt resistance per BY255?
Online searches tell me to take the Rated Voltage of the diode x 500V
Which in my case would be 650kohms...
I cannot verify that is a good value with my current knowledge and experience.
Anyone can direct me to any source of writeups so i can understand more on how this value of 500V came about?
Thanks,
Nash78