1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Melting ice

  1. Dec 11, 2005 #1
    How much ice could be melted by 320. grams of water at 68.0 degrees C?
    Would I us mL + mcT=0 for the equation, and do the latent heat of ice for the first part and water for the second?
     
  2. jcsd
  3. Dec 11, 2005 #2

    Astronuc

    User Avatar
    Staff Emeritus
    Science Advisor

    One must determine the energy (heat) from the mass of water decreasing from 68°C to 0°C. Then determine what mass of ice would be transformed to water at 0°C.

    Assuming that L in your equation is latent heat, and by T you mean change in temperature, you are correct.

    The heat from the liquid, Q, is just the change in energy in the liquid, i.e. Q = [itex]\Delta\,H[/itex] = [itex]m\,c\,\Delta\,T[/itex], where c is specific heat.
     
  4. Dec 11, 2005 #3
    So it would be m(333.7kJ/kg)+(.320kg)(4.186kJ/kg*K)(-68.0K)=.273kg of ice Is this correct?
     
  5. Dec 11, 2005 #4

    Astronuc

    User Avatar
    Staff Emeritus
    Science Advisor

Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Melting ice
  1. Ice melting (Replies: 1)

  2. Melting ice (Replies: 3)

  3. Melting ice (Replies: 2)

  4. Melting Ice (Replies: 4)

  5. Ice Melting (Replies: 3)

Loading...