# Melting point of a solid

1. Nov 2, 2006

How would I show that the melting point of a solid decreases with increasing pressure knowing that the specific volume of the liquid is less than the solid?

dP/dT=delta h / (T delta v) Clapeyron equation

Inverse it:
dT/dP = (T delta v)/delta h
v" < v' : molar volume vapor < mol. volume liquid

Not sure where to go from there

2. Nov 2, 2006

### stunner5000pt

well couldnt you say this:

$$\Delta P = \frac{L_{f}}{\Delta V} \frac{\Delta T}{T}$$

and since the change in P and T are inversely proportional, a posotive change in P increases melting point T.

just my \$0.01