I really honestly believe that I worked this out correctly, and explained my logic.. but I just wanted to have this checked to be on the safe side. Thanks a lot for helping, I appreciate the time everyone puts into reading this ^^;; 1. The problem statement, all variables and given/known data Mercury is poured into a U tube in which the cross sectional area of the right limb is three units larger than the left one. The level of mercury in the narrow limb is 30 cm from the upper end of the tube. How much will the mercury level rise in the right limb when the left limb is filled to the top with water? 2. Relevant equations (p_w)(g)(h_w)(A_1) = (p_m)(g)(h_m)(A_2) Where m = mercury, w = water, p = density, g = 9.8 m/s^2, h = height, and A = area (h_m) = (p_w)(h_w)(A_1) / (p_m)(A_2) 30 cm = .30 m Density of water = 1000 kg/m^3 Density of mercury = 13,600 kg/m^3 3. The attempt at a solution (h_m) = (1000 kg/m^3)(x)(.3m) / (13,600 kg/m^3)(3x) = .007m The x's cancel out.. unit left remaining is just m on top because you want height, which is in meters. Logically speaking, since the limb on the right is 3x as large the height of the mercury will not be as great as .30 m on the other side because the area is larger. So .007 m sounds like a reasonable number. Also considering the density of mercury is much larger than that of water, it makes sense that not a very large height at all is needed to hold all the mercury.