(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A carnival merry-go-round rotates about a vertical axis at a constant rate. A man standing on the edge has a constant speed of 3.66 m/s and a centripetal acceleration a of magnitude 1.83 m/s2. Position vector r locates him relative to the rotation axis. a) what is the magnitude of r? What is the direction of r when a is directed b) due east and c) due south?

2. Relevant equations

a = v^2/r

T = 2pi r/v

3. The attempt at a solution

a) no idea how to do this part.

b) i thought since acceleration is east, which would be toward centre because circular motion, then wouldn't position be same direction??

c) same as b

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# Homework Help: Merry Go-Round Circular Motion

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