A 5.4m diameter merry-go-round is rotating freely with an angular velocity of 0.730 rad/s. Its total moment of inertia is 1665kg*m2. Four people standing on the ground, each of mass 60.8kg, suddenly step onto the edge of the merry-go-round. What is the angular velocity of the merry-go-round now? Use units of "rad/s".(adsbygoogle = window.adsbygoogle || []).push({});

r = 2.7 m

w= .730 rad/s

I= 1665 kg*m2

I'm not sure if i'm doing this right but what i did was i set the inertia equal to mk^2. By doing this i was able to find the initial mass to be 228.395 kg. Then i added the weight of the four people to this mass and got 471.595 kg. Then I solved for that moment of inertia to be (471.595)(2.7)^2 which ended up being 3437.93kg*m2. Now i'm not sure how to find the angular velocity...I tried to just set the values equal to one another, hoping the proportion would produce the right value but that didn't work. I have no idea...

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# Homework Help: Merry-go-round problem

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