1. The problem statement, all variables and given/known data Use the mesh-current method to find v0. Find the power delivered by the dependent source. 2. Relevant equations v1+v2+..vn=0 i=v/R p=iv 3. The attempt at a solution eq #1)-i1*10+i2*20=25V eq #2) i2*20+i2*24+6iΔ=0 eq #3) iΔ*14=21 eq#3) iΔ=1.5A eq#3 sub into eq#2) i2=0.204A i2 sub into eq#1) -1.6A Power delivered= p=iv p=0.204A*(6*1.5)V = 1.839 W I posted the solution below. I don't understand how they got it. They added up resistances, and also said i1*20 in the first equation, but i2*20 in the second. Also, I'm not sure how to get the polarities when the + and i signs aren't given. For example, the 24Ω resistor.