A meteor has a speed of 83.0 m/s when 811 km above the Earth. It is falling vertically (ignore air resistance) and strikes a bed of sand in which it is brought to rest in 3.31 m. What is its speed just before striking the sand? So here is the formula that I have but it doesn't give me the right answer. v=square root of (Vi^2 + 2G(Mass of the Earth)/(Radius of the Earth*1-1/3.31) I get 9337.6 m/s. Does anyone see where my mistake is?