Consider the classic image problem with a conducting plane and a point charge. After finding out the charge density on the plane we integrate to find out the total charge induced. It comes out to be "-q",where q is the charge outside-(adsbygoogle = window.adsbygoogle || []).push({});

My book says "It comes out to be -q, as you can convince yourself with the benefit of hindsight". It isn't that obvious why it should come out equal to the image charge. Can somebody explain?

**Physics Forums - The Fusion of Science and Community**

# Method of Images

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

- Similar discussions for: Method of Images

Loading...

**Physics Forums - The Fusion of Science and Community**