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Metric tensor

  1. Feb 11, 2013 #1
    Am i correct in thinking that in a simple [itex]ds^2 =dt^2 - a^{2}d\underline{x}^{2}[/itex] metric that:
    [itex]g_{\mu\nu}=diag(1,-a^2,-a^2,-a^2)[/itex] and [itex]g^{\mu\nu}=diag(1,-\frac{1}{a^2},-\frac{1}{a^2},-\frac{1}{a^2})[/itex]

    thx
     
  2. jcsd
  3. Feb 11, 2013 #2

    Fredrik

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