1. The problem statement, all variables and given/known data If the field diameter on 40X is 1600 µm, and a specimen takes up one quarter of the field, how big is the specimen in real life? 2. Relevant equations Magnification of image= Image size/ Real size of object 3. The attempt at a solution I'm not sure but in the formula, would be put the magnification of the image as 40 and image size as 1600 µm and solve? or would we simply find one quarter of 1600 µm and that would be the actual size of the specimen..? I'm a little confused so could help me clear things up about the differences between the two?