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dv/dt = 9.8 - Cv/D^2

Where C= 3.1*10^-6 m^2/s and D is the diameter in metres. The oil drop is assumed to start from rest.

Solve the differential equation and hence show that the eventual (terminal) velocity in terms of D is v(t)=9.8D62/C

I have tried several times to integrate this question without success, I think I am making the mistake right at the start. Any help would be greatly appreciated.