- #1

aaaa202

- 1,170

- 3

l=-(h+k) (1)

Given the basis vectors a1,a2,a3 I can certainly see that:

a3=-(a1+a2)

But how does this immidiatly lead me to the relation (1) between the miller indices?

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- Thread starter aaaa202
- Start date

- #1

aaaa202

- 1,170

- 3

l=-(h+k) (1)

Given the basis vectors a1,a2,a3 I can certainly see that:

a3=-(a1+a2)

But how does this immidiatly lead me to the relation (1) between the miller indices?

- #2

DrDu

Science Advisor

- 6,256

- 906

If you really encounter problems, we all are willing to help you.

- #3

The redundancy in coordinate implies the relationship

- #4

nasu

- 3,957

- 583

Given the basis vectors a1,a2,a3 I can certainly see that:

a3=-(a1+a2)

But how does this immidiatly lead me to the relation (1) between the miller indices?

How do you define these basis vectors? Is a3 in the same plane as a1 and a2?

- #5

aaaa202

- 1,170

- 3

Yes they are are all with a 60 degree angle relative to each other.

- #6

aaaa202

- 1,170

- 3

- #7

nasu

- 3,957

- 583

Sorry, I was confused.

- #8

aaaa202

- 1,170

- 3

yes exactly, 3 vectors in the hexagonal plane, one in the c-direction

- #9

M Quack

- 899

- 67

G = H a* + K b* + L c*(for the "normal" 3 Miller indices).

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