Can somebody tell me what is the miller index for the tilted plane? Is it (102) or (112)? Nothing seems to fit... I wonder if we can even describe it with miller index? Please download the picture here in pdf format: http://www.megaupload.com/?d=F8J344BH Thanks!
Every plane has a Miller index. A common way to find the Miller index for a plane in a cubic system is to take the reciprocal of the axis intercepts and normalize the result so it contains only integers. Negative intercepts are treated by putting a bar over the number. For example, the y-intercept in your figure is at -1.
thanks for the reply. But could you explain why is the y intercept for the triangular plane -1? it does not seem to intersect with the y axis?
The plane continues on to infinity; if you follow the line in the y-z plane, you'll see that it (and therefore the plane) intersects the y-axis at -1. Use the same approach for the other axes.
um..so are you saying that I can extend the vector so it eventually intersects with the y-axis? so the miller index should be (1-12)?
Yes; a [itex](1\bar 1 2)[/itex] plane (a member of the family of [itex]\{112\}[/itex] planes), with surface normal vector [itex][1\bar 1 2][/itex] (a member of the family of [itex]\langle 112\rangle[/itex] directions).