# Min and max value of moment

1. Mar 29, 2008

### Altairs

1. The problem statement, all variables and given/known data

The 70N force acts on the end of the pipe at B. determine the angles theta between 0 and 180 of the force that will produce maximum and minimum moments about point A.

2. Relevant equations

FBD is attached.

3. The attempt at a solution

I made the following equation then took its derivative and put it equal to 0. The problem here is that I only get one value of theta. the one which gives the maximum value of the moment. there isn't any other value of tan coming withing 0-180. How do I get the minimum value of theta from this method. Wasn't I automatically supposed to get two value of theta from the first derivative and then I could I have gone further to second derivative to check if it was min or max. I am stuck.

Equation :- $$M = (70cos\theta * 0.9) + (70sin\theta * 0.7)$$
Derivative :- $$= -63sin\theta + 49cos\theta$$

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2. Mar 29, 2008

### tiny-tim

Hi Altairs!

(btw, I haven't seen the picture yet)

erm … sometimes it's maths, and sometimes it's just looking at the reality.

It often helps to draw a diagram (roughly).

The graph of the moment should look like a hill.

At 0º, the derivative is 49, which is positive; at 180º, it is -49, which is negative.

So the moment is already increasing at 0º, and is still decreasing at 180º.

So one of them may be a minimum …

3. Mar 30, 2008

### Altairs

Sorry. Can't get it. Would be easier with a few equations.

4. Mar 30, 2008

### tiny-tim

Hi Altairs!

(Still can't get the picture - I keep getting the please-log-in screen! )

At 0º, the moment is 63; it goes up until tantheta = 7/9; then it goes down until, at 180º, it is -63.

So the maximum is at tantheta = 7/9, them minimum is at 180º.