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Minimal polynomial

  • Thread starter cristina89
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  • #1
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Homework Statement


Given the matrix
2 0 0 0 0 0 0
1 2 0 0 0 0 0
0 1 2 0 0 0 0
0 0 1 2 0 0 0
0 0 0 0 2 0 0
0 0 0 0 1 2 0
0 0 0 0 0 0 2

What is the minimal polynomial?

Homework Equations



-

The Attempt at a Solution



This is the Jordan form, so I guess the solution is just m(t) = (t-2)7 but I don't know if it's right. Can anyone help me?
 

Answers and Replies

  • #2
I like Serena
Homework Helper
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176

Homework Statement


Given the matrix
2 0 0 0 0 0 0
1 2 0 0 0 0 0
0 1 2 0 0 0 0
0 0 1 2 0 0 0
0 0 0 0 2 0 0
0 0 0 0 1 2 0
0 0 0 0 0 0 2

What is the minimal polynomial?

Homework Equations



-

The Attempt at a Solution



This is the Jordan form, so I guess the solution is just m(t) = (t-2)7 but I don't know if it's right. Can anyone help me?
Hi cristina89! :smile:

The minimal polynomial P of a square matrix A is the unique monic polynomial of least degree, m, such that P(A) = 0.

The degree of the minimal polynomial is determined by the size of the largest Jordan block, which is 4 in your case.
So the minimal polynomial is m(t) = (t-2)4.

Indeed ##(A-2I)^4=0##.
 
  • #3
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Thank you so much!! :)
 
  • #4
Ray Vickson
Science Advisor
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Thank you so much!! :)
The method suggested above is by far the simplest way to deal with this specific problem, but in a more general case you can use the algorithms employed by computer algebra systems, such as Maple: regard A, A^2, A^3,... as n^2-dimensional vectors, then find the smallest k such the vectors I, A, A^2,..,A^k are linearly dependent---essentially, using standard linear algebra methods. This will also deliver the coefficients and hence the minimal polynomial.
 

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