Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Minimal Time, hmm.

  1. Jan 13, 2004 #1
    I was in my Calculus class and a problem came up that I couldn't figure out. Our teacher wrote down a problem on the board to test us on the upcoming exam next week and he called upon us randomly, but no one got it. I thought I figured it out, but I was off. Hopefully you can help me here.

    A person on a boat in a lake is 9 km from the shore and must go to a
    point 12 km down the shoreline in the shortest possible time. The
    person can walk 8 km per hour and the boat can travel r km per hour.

    a) Assume that the person should travel by boat and by foot. Let d be
    the distance down the shoreline the person should strike land for the
    shortest total travel time. Write d as a function of r.

    b) Sketch the graph of the function d(r). Determine the slowest speed
    of the boat so the shortest possible time criterion is met by making
    the entire trip by water. Use this to give the domain of the function
    in the context of this problem.

    c) Determine the concavity of the graph of the function d over the
    domain stated in part b. What information does the concavity give about the relation between d and r?
    Our class attempted this problem and wrote an equation based on the
    given information. We took the derivative of our equation to find the
    answer to part a, but the answer we arrived at was different from the
    answer given in the book. Our answer was d=(r-36)/4, from the equation d(r) = r * sqrt(d^2+81) + 8(12-d). As stated, d is the distance down the shoreline where the person should strike land. Thus 12-d is the distance from the point where the person lands to his or her destination. Using the Pythagorean Theorem, we found the distance from the boat to the point where the person will land to be the square root of (d^2 + 81). The answer the book gave us is d(r) = 9r/sqrt(64-r^2).

    I, (and the class can't figure out) or understand what we did wrong, and I hope someone will be able to help me for tomorrow since no one figured it out. Some got close, but no one got it completely.

    Here is what I think:

    I believe that we were writing d in terms of rate, not rate and time, so we need to get rid of the time component, right? Then time for the trip is t = sqrt(d^2+81)/r + (12-d)/8, right? So then you would differentiate it?

    But then I get lost. :)
  2. jcsd
  3. Jan 13, 2004 #2


    User Avatar
    Science Advisor
    Homework Helper


    Now, the derivative with respect to [tex]d[/tex]:

    The derivative of the second term is clearly:
    So that leaves the first term.
    If you apply the chain rule, you get:
    [tex]\frac{1}{r} 2d \frac{-1}{\sqrt{d^2+81}}[/tex]

    So now, you need to solve:

    Then you can check those solutions, and the endpoints to see which is the optimal solution
  4. Jan 14, 2004 #3
    Thank you, NateTG I really appreciate you showing the steps. I figured out what I was doing wrong.

    Thanks again.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Minimal Time, hmm.
  1. Minimization Problem (Replies: 7)

  2. Minimal Function (Replies: 16)

  3. Distance Minimization (Replies: 4)