- #1

- 18

- 0

## Homework Statement

The objective is to minimize

[itex]J(x) = \int y^2 (x+y)^2 dy, [/itex]

where x is the design variable.

## The Attempt at a Solution

I first integrate over y to get

[itex] J(x) = \frac{x^2 y^3}{3} + \frac{y^5}{5} + \frac{2x y^4}{4}[/itex]

Now, I differentiate over x, and solve for the minimizer, the result is

[itex] x_{\textrm{min}} = \frac{-3y}{4}[/itex]

My question is the following: If I look at the cost function, I feel that the minimizer should be zero. Why am I getting [tex]\frac{-3y}{4}[/itex] as the minimzer?

Background:

I heard somewhere that if you want to minimize

[itex] J(x) = \int f(y) f(x,y) dy [/itex],

where [itex]f(x)>0[/itex] and [itex]f(x,y)>0[/itex], then you can just obtain the minimizer by minimizing f(x,y). So I constructed the example above and it doesn't work. Can anyone point to a theorem that lists this kind of result?

Thanks.

Last edited: