Minimum Angular Speed

  • Thread starter evan4888
  • Start date
  • #1
11
0
The ROTOR is an amusement park ride where people stand against the inside of a cylinder. Once the cylinder is spinning fast enough, the floor drops out. If the coefficient of friction is 0.42 and the cylinder has a radius of 2.5m, what is the minimum angular speed of the cylinder so that the people don't fall out?

How would I go about solving this? I don't even know where to start!
 
Last edited:

Answers and Replies

  • #2
1,036
1
let m = mass of a person
let n = normal force exerted on the person by the (spinning) cylinder wall
let μ = the coefficient of friction
let g = acceleration of gravity

Start by thinking about the forces acting on the person along the vertical axis (up and down) in terms of the above. What has to be true if the person doesn't fall? Set up the appropriate equation to express this.

Then, think about what produces the normal force and you should be able to find your answer.
 
  • #3
11
0
I think I know how to find the max cetripetal acceleration with ac = v2/r or
v = sq. root of r(ac). But without knowing the weight of the people inside the ride, I just don't understand how you would find the minimum angular speed.
 
  • #4
1,036
1
It's the speed that gives you the n that you need.

You do know the weight: mg. The m will eventually cancel out.
 

Related Threads on Minimum Angular Speed

  • Last Post
Replies
6
Views
15K
Replies
1
Views
2K
  • Last Post
Replies
4
Views
4K
  • Last Post
Replies
3
Views
8K
  • Last Post
Replies
5
Views
496
  • Last Post
Replies
7
Views
1K
  • Last Post
Replies
1
Views
3K
  • Last Post
Replies
4
Views
3K
  • Last Post
Replies
1
Views
15K
Top