A ray of light is incident in air at an angle of 40 degrees to the normal to one face of a 60 degree glass prism. Calculate the angle through which the ray has been deviated by the time it emerges from the prism. (refractive index of glass wrt air is given as 1.50)
I tried using the formula:
n1 = sin(A+D)/2 [tex]\div[/tex] sin(A/2)
where D = 2i - 2r & A = 2r
The Attempt at a Solution
i am not sure how to approach the question, i dont know where to include the angle of incidence, the solution is supposed to be 38.5 degrees. Please, can someone help me out! thanks!