Minimum Initial Velocity

In summary, the conversation discusses the minimum positive initial velocity necessary for an object to reach a height of 80 meters from ground level. The given kinematic equation is vf2 = v02 - 2gy, where vf is the final velocity, v0 is the initial velocity, g is the acceleration due to gravity, and y is the displacement. Using this equation, the minimum initial velocity is found to be 40m/s.
  • #1
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This seems a simple enough question, but I am not sure on how to go about solving it

"What is the minimum positive initial velocity necessary for an object to be launched from ground level so that it reaches a height of 80 meters?"

Multiple choice answers: a) 5m/s
b) 9.8m/s
c) 12.5m/s
d) 40m/s
e) 80m/s

Well the problem doesn't give me a time, so I am guessing it is asking that the object reaches at least 80m before it starts its fall back down. Can someone attempt to explain how I would get the answer? If I were simply guessing, I would go with either C or D, however, that's only guessing. I am sure gravity would someone used, but I don't know what to do with it.
 
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  • #2
Let's see, we are given explicitly the maximum height of the object as 80 meters. If we make the assumption the object is close to a flat Earth approximation, then the acceleration acting on the object is -g. Implicitly, we can that if the object just goes the minimum height of 80 meters, then its final velocity would be zero. Kinematically, this gives us the relation:

vf2 = v02 - 2gy

This is assuming it is thrown straight up. Would the initial velocity be greater or less if the object is thrown up at an angle?
 
  • #3
Ok, so using the formula vf2 = v02 - 2gy, I can plug in the numbers as such: 0 = x^2 - 2(9.8)(80) where x is the initial velocity. This reduces to x^2 - 1568. Now, I am assuming that I can simply plug in the choices for x, which means I can square each choice, and if it is greater than 1568, it will reach 80m.

Choice D, 40m squared will give me 1600, which is the closest to 1568 and the minimum initial velocity.

Does that sound right, or did I just stack assumptions to get my answer?
 
  • #4
Looks correct to me.
 
  • #5
D is correct, but I think you are making it more difficult that it actually is. The given kinematic equation only has one unknown, v02. Just isolate the variable and take the square root of both sides.
 
  • #6
you're right physics.guru, when I isolated the variable, it came out to 39.6, which is close enough to 40.
 

1. What is the definition of minimum initial velocity?

Minimum initial velocity refers to the minimum speed at which an object must be launched or thrown in order to reach a certain distance or height. It is affected by factors such as air resistance and gravity.

2. How is minimum initial velocity calculated?

The calculation for minimum initial velocity depends on the specific situation and can involve equations related to distance, acceleration, and time. It also requires consideration of external factors such as wind and air resistance.

3. What is the significance of minimum initial velocity in physics?

Minimum initial velocity is an important concept in physics as it helps determine the necessary speed for an object to reach a desired distance or height. It is also useful in analyzing projectile motion and other types of motion.

4. Can minimum initial velocity ever be zero?

In theory, yes, it is possible for minimum initial velocity to be zero if there is no resistance or external forces acting on the object. However, in practical situations, this is highly unlikely as there is always some resistance or force present.

5. How does air resistance affect minimum initial velocity?

Air resistance can significantly impact the minimum initial velocity required for an object to reach a certain distance or height. The greater the air resistance, the higher the minimum initial velocity needed to overcome it and achieve the desired result.

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