# Minimum/Maximum magnitude

1. Sep 23, 2007

### noeinstein

1. The problem statement, all variables and given/known data

For women's volleyball the top of the net is 2.24 m above the floor and the court measures 9.0 m on each side of the net. Using a jump serve, a player strikes the ball at a point that is 3.05 m above the floor and a horizontal distance of 8.3 m from the net.

(a) If the initial velocity of the ball is horizontal, what minimum magnitude must it have if the ball is to clear the net?

(b) What maximum magnitude can it have if the ball is to strike the floor inside the back line on the other side of the net?

2. Relevant equations

V(o)=R x sqrt(g/2h)

3. The attempt at a solution

My wild attempt
H in relation to the top of the net = 3.05m - 2.24m = 0.81m
V(o)= 8.3 x sqrt(9.8/2 x .81) = 16.54

2. Sep 23, 2007

### Staff: Mentor

Mostly correct, but V(o)=R x sqrt(g/(2h))

or $$v_0\,=\,R\sqrt{\frac{g}{2h}}$$

3. Sep 23, 2007

### noeinstein

Thank you much sir for your time!