brentwoodbc said:I know
w=fd
f=ma
f=65x9.8
f=5096
but that doesn't have time or distance.
fluidistic said:It seems you got the answer!
The minimum work needed would be done by a force acting upward, in the opposite direction of the weight. Its magnitude would have to be greater than the weight, so >65 kg*9.8m/s^2 as you did.
You wrote w=fd, where w is the work, f is the force and d is the distance. Then you said that the formula doesn't have a distance?
Well you've done it :)
A minimum work physics problem is a type of problem where you are given a system and asked to find the minimum amount of work that needs to be done to achieve a certain outcome. This involves understanding the forces and energies involved in the system and using the laws of physics to determine the minimum work required.
To solve a minimum work physics problem, you first need to identify all the forces and energies involved in the system. Then, you can use the principles of work and energy, such as the work-energy theorem and the conservation of energy, to determine the minimum work required.
Sure! An example of a minimum work physics problem is a block being pulled up a ramp by a force. The question might ask for the minimum work required to move the block from the bottom to the top of the ramp.
One common mistake is forgetting to account for all the forces and energies involved in the system. Another mistake is using the wrong equations or not properly applying the principles of work and energy.
Understanding minimum work physics problems can be useful in many fields, such as engineering, architecture, and transportation. It allows us to determine the most efficient and cost-effective ways to accomplish tasks and achieve certain outcomes.