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Mirror and Lens Optical System

  1. Nov 5, 2012 #1
    1. The problem statement, all variables and given/known data
    Optical System:
    Biconcave lens and convex mirror separated by distance 'L'.
    Object placed 0.40m in front of the lens.
    Final image is .12m from the vertex of the mirror

    Lens curvature radii: 0.10m and 0.20m
    Mirror curvature radii: .12m

    Calculate the distance 'L'


    2. Relevant equations

    1/S + 1/S' = 1/f = (n2-n1)/n1 . (1/R1 - 1/R2)

    1/S + 1/S' = -2/R


    3. The attempt at a solution
    Calculated where the lens creates an image using the first equation and got an answer of -0.20m, seen as the image would be virtual due to it being a divergent lens.
    Then calculated where the mirror thought the object was using the second formula rearranged for S and got 0.086m.

    Does that not mean the mirror is closer than the lenses?


    EDIT: Actually got the sign wrong got -0.086m, so a virtual image, so now I have two virtual images, so I'm lost.
     
  2. jcsd
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