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**1. Homework Statement**

Optical System:

Biconcave lens and convex mirror separated by distance 'L'.

Object placed 0.40m in front of the lens.

Final image is .12m from the vertex of the mirror

Lens curvature radii: 0.10m and 0.20m

Mirror curvature radii: .12m

Calculate the distance 'L'

**2. Homework Equations**

1/S + 1/S' = 1/f = (n2-n1)/n1 . (1/R1 - 1/R2)

1/S + 1/S' = -2/R

**3. The Attempt at a Solution**

Calculated where the lens creates an image using the first equation and got an answer of -0.20m, seen as the image would be virtual due to it being a divergent lens.

Then calculated where the mirror thought the object was using the second formula rearranged for S and got 0.086m.

Does that not mean the mirror is closer than the lenses?

EDIT: Actually got the sign wrong got -0.086m, so a virtual image, so now I have two virtual images, so I'm lost.