1. The problem statement, all variables and given/known data Optical System: Biconcave lens and convex mirror separated by distance 'L'. Object placed 0.40m in front of the lens. Final image is .12m from the vertex of the mirror Lens curvature radii: 0.10m and 0.20m Mirror curvature radii: .12m Calculate the distance 'L' 2. Relevant equations 1/S + 1/S' = 1/f = (n2-n1)/n1 . (1/R1 - 1/R2) 1/S + 1/S' = -2/R 3. The attempt at a solution Calculated where the lens creates an image using the first equation and got an answer of -0.20m, seen as the image would be virtual due to it being a divergent lens. Then calculated where the mirror thought the object was using the second formula rearranged for S and got 0.086m. Does that not mean the mirror is closer than the lenses? EDIT: Actually got the sign wrong got -0.086m, so a virtual image, so now I have two virtual images, so I'm lost.