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Mirror and Lens Optical System

  • Thread starter chris_avfc
  • Start date
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1. Homework Statement
Optical System:
Biconcave lens and convex mirror separated by distance 'L'.
Object placed 0.40m in front of the lens.
Final image is .12m from the vertex of the mirror

Lens curvature radii: 0.10m and 0.20m
Mirror curvature radii: .12m

Calculate the distance 'L'


2. Homework Equations

1/S + 1/S' = 1/f = (n2-n1)/n1 . (1/R1 - 1/R2)

1/S + 1/S' = -2/R


3. The Attempt at a Solution
Calculated where the lens creates an image using the first equation and got an answer of -0.20m, seen as the image would be virtual due to it being a divergent lens.
Then calculated where the mirror thought the object was using the second formula rearranged for S and got 0.086m.

Does that not mean the mirror is closer than the lenses?


EDIT: Actually got the sign wrong got -0.086m, so a virtual image, so now I have two virtual images, so I'm lost.
 

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