Misc integral

  • Thread starter nameVoid
  • Start date
  • #1
241
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[tex]
\int \frac{x}{\sqrt{3-x^4}}dx
[/tex]
[tex]
u=x^2
[/tex]
[tex]
du=2xdx
[/tex]
[tex]
\frac{1}{2}\int\frac{du}{\sqrt{3-u^2}}
[/tex]
[tex]
u=\sqrt{3}sinT
[/tex]
[tex]
du=\sqrt{3}cosTdT
[/tex]
[tex]
\frac{1}{2}\int \frac{\sqrt{3}cosT}{\sqrt{3}cosT}dT

[/tex]
[tex]
\frac{x}{2}+C
[/tex]

Homework Statement





Homework Equations





The Attempt at a Solution

 

Answers and Replies

  • #2
Dick
Science Advisor
Homework Helper
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Not x/2+C. T/2+C.
 
  • #3
10
0
You need not do the second u-substitution. Use an integral table to solve it once you have done the first u-substitution. You can google 'integral table' to find one if you don't have one in your book.
 

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