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No, I just wanted to shift it into the interval injectively. The amount didn't matter. With ##\frac{1}{4}## I would have had to deal with the zero, which I avoided by taking ##\frac{1}{3}##.If I understand what your notation conveys, the last bit should be ## \stackrel{+\frac{1}{4}}{\hookrightarrow} (0,1)##, since you're adding 1/4 to each element of the punctured interval (-1/4, 1/4).