1. The problem statement, all variables and given/known data 300gm of water at 25°C is added to 100gm of ice at 0°C ,find the final temperature of the mixture .Also find the final composition of mixture . 2. Relevant equations Specific heat of water = 1 cal/gm/°C Latent heat of fusion of ice = 80 cal/gm 3. The attempt at a solution Heat released by 300gm water to reach 0°C = 300x1x25 = 7500 cal Heat required by ice to melt completely = 100x80= 8000 cal Since heat supplied is less than heat required , whole ice will not melt . Amount of ice melted = 7500/80 = 93.75gm Final composition of mixture = 393.75gm water +6.25gm ice at 0°C Is my answer correct ?