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Mixing Ice & Water help me Obe Wan

  1. Mar 3, 2013 #1
    1. The problem statement, all variables and given/known data

    An 18g ice cube at -4.0ºC is placed into 75g of water at 10 ºC in an
    insulated container.
    a. What is the final temperature of the system?
    b. How much of the ice melts?

    I have a sheet full of these & ice to water to steam I really need somone to explain how to find the results so I can get my brain around these

    2. Relevant equations
    Q=MCΔT
    C ice =2.09j/g°c
    Cwater = 4.186j/g°c
    M=Mass in g
    T = temp in Degrees C

    Q=ML
    M=Mass in g
    Lice =334j/g

    3. The attempt at a solution
    So heres what i think is right so far
    Raise the temp of ice to 0
    18 x 2.09 x 4 = 150 joules
    Remove this energy from the water
    150.48=75 x 4.186 x(10-Tf)is this part right?
    150.48= 3139.5-313.95(Tf)
    I am not sure how to get to the resultant temp of the water propery before I consider a phase change in the ice but I have a feeling there wont be enough heat energy in the water to melt all of the ice.
     
    Last edited: Mar 3, 2013
  2. jcsd
  3. Mar 3, 2013 #2
    So heres what i think is right so far
    Raise the temp of ice to 0
    18 x 2.09 x 4 = 150 joules
    Remove this energy from the water
    150.48=75 x 4.186 x(10-Tf)is this part right?
    150.48= 3139.5-313.95(Tf)
    I am not sure how to get to the resultant temp of the water propery before I consider a phase change in the ice but I have a feeling there wont be enough heat energy in the water to melt all of the ice
     
  4. Mar 3, 2013 #3
    or to remove the energy is it simply 150.48 = 75 x 4.186 x Tf
    150.48 = 315.95 (T?)
    T? = 150.48/313.95
    T? = 0.483degrees C
    then remove this from the initial temp of water
    10 - 0.483 = 9.517 Deg C is this right so far?
     
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