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Mixing ice with water

  1. Apr 10, 2008 #1
    1. The problem statement, all variables and given/known data

    If you mixed 200g if ice that is at -5°C with 20g of water that is at 15°C, what will be the temperature and condition of the final state once equilibrium is achieved?


    2. Relevant equations
    Q=mcΔT, Q=mLf


    3. The attempt at a solution
    I know that the amount of ice is to great to change with such little water, so I know the final condition will be a 220g block of ice at some temperature between -5°C and 0°C. Since the mass of the water is added to the mass of the ice does this imply that Qgained≠Qlost?

    That's what I'm having trouble on, deriving the equation to solve for temperature if they are not equal.
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Apr 11, 2008 #2
    Go ahead with your equations and whatever you know.i shall help ya along.
     
  4. Apr 11, 2008 #3
    Hi DBW, have you considered the phase change involved? :smile:
     
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