- #1

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Using the previous equations derived earlier

n

_{dOH}= (P*Av/R*T)*C

_{OH}

(n

_{dOH}*R*T/(P*Av) ) = C

_{OH}

(10^6 molecules/cm^3)*(1 cm/100 m)*(1 cm/100 m)*(1 cm/100 m) = 1 molecule/m^3

((1 molecule/m^3 )*(8.314 J/mol*K)*(298 K)/(10^5 Pa)(6.022*10^23)) = C

_{OH}

2477.572/6.022*10^23= 4.11*10^-21

Is this process correct? Thanks.