let be the sum (over all the divisors d of n):(adsbygoogle = window.adsbygoogle || []).push({});

[tex] f(n)= \sum_{d|n} \mu (n/d)g(d) [/tex] my question is if n=prime then you have only 2 numbers 1 and p that are divisors so you get:

[tex] f(p)= \mu (p)g(1) + \mu (1) g(p) [/tex] is that correct?...now the question is to know what's the value of mu(x) function for x=1 or p. :uhh:

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# MObius transform sum

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