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I am trying to model a lense shape using two circles of radii R and r, with one at the origin and the other offset upwards vertically by distance D. D must be less than R + r, but it must be greater than the larger of R or r.

Thus, I have two equations, and the region of their intersection is a lense-shape!

[tex]x^2 + y^2 = R^2[/tex] called the "origin sphere"

[tex]x^2 + (y - D)^2 = r^2[/tex] called the "offset sphere"

Anyway, for the numerical analysis I'm doing, I have R = r = 5 (the size of my protractor) and D = 8, which works out nicely because the two circles intersect at (-3, 4) and (3, 4).

What I do:

-start off with incident light, represented by vertical rays, like x = 2

-find the point at which it collides with the offset sphere (x_{ray}, y_{ray})

-draw a tangent (using the derivative)

-find the necessary angles (using the arctangent of slope)

-use Snell's law once ([itex]n_{air} \sin{\theta_1} = n_{glass} \sin{\theta_2}[/itex])

-determine an equation of a line y that has this equivalent angle and passes through the collision point: y = m(x - x_{ray}) + y_{ray}

-find there this new line collides with the origin sphere (the top curve of the lense)

-draw a tangent

-Snell's law again

-determine an equation of the final line, the twice-refracted line

-the y-intercept of that line is the "focal" point (judging by symmetry)

This is a lengthy process, each of these steps involving not-very-simplifyable expressions, so a "master equation" that does all this for me would be unwieldy.

What I have found, though (to my great disappointment), is that the "focus" is actually a region of intersections and not simply one point. So, I'm trying to think,would adding a second "lense" remove all spherical aberration?Is it even possible to remove all spherical aberration? By "lense", I mean any extra, defineable shape that will correct the aberration.

Thanks!

-Unit

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# Modeling a lense using the intersection of two spheres

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