Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Modeling A Problem Situation:

  1. Oct 30, 2005 #1
    Okay, here is the problem, ; Remesh likes to run outdoors and ride his bicycle at the veledrome. He burns about 400 calories/h running, and 300/h riding his bike. It costs $6/h to ride in the veledrome. Ramesh hopes to develope a weekly exersise program that will burn 4800 calories, cost no more than $24, and require a maximum of 8 hours...... Now I need the restrictions to graph this problem, (x=running/h; y=bike/h) I so far have; x (> or equal to) 0, y (> or equal to) 0, x+y (< or equal to) 8, and y (< or equal to) 4. I think I'm missing one, and think it might have to do with the calories, so is 400x+300y (> or equal to) 4800. But would it be applicable to the hour restriction? Thanks in Advance!
     
  2. jcsd
  3. Oct 31, 2005 #2

    verty

    User Avatar
    Homework Helper

    Intuitively, the most calories will be burnt by running. 8 hours of running will burn 3200 calories, so it is impossible to get 4800 from 8 hours of exercise.

    When you plot the inequalities, the solution lies in the intersection of the areas. When you plot the fifth inequality (400x + 300y >= 4800) you'll find the areas do not intersect, so there is no solution.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Modeling A Problem Situation:
  1. Modeling a treybuchet (Replies: 3)

  2. Mathematical Modeling (Replies: 1)

  3. Gaussian model (Replies: 1)

Loading...