- #1

sephy

- 5

- 0

**1. If a**

_{1},...,a_{n}is a list of (not necessarily distinct) elements of a group G, then, for all i, a_{i}...a_{n}a_{1}...a_{i-1}is conjugate to a_{1},...,a_{n}.## Homework Equations

## The Attempt at a Solution

I know that you have to prove the existence of an element g of the group G such that ga

_{1},...,a

_{n}g

^{-1}= a

_{i}...a

_{n}a

_{1}...a

_{i-1}, but I don't know how to find this element g, or how to define it or it's inverse. Very confused.