For n in N (Natural Numbers), use modular arithemetic to establish each of the following divisibility statements:(adsbygoogle = window.adsbygoogle || []).push({});

a) 7 | 5^{2n}+ 3 (2^{5n - 2})

Attempt: Well I've set up a mod 7 table and was figuring out the values from n = 0,....6 for the two individual expressions, then I was going to combine them. But I of course hit a rough patch when I got to 2^{5n - 2}. Since I'm in the Natural numbers, fractions do not exist, so how do I treat 2^{5n - 2}when n = 0 ?

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# Modular Arithemetic Question

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