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## Homework Statement

Show that if a = (b mod m) and c = d(mod m) and m => 2, then a - c = (b - d)(mod m)

## Homework Equations

c = d(mod m) <=> m|(c - d)

d = c + xm

## The Attempt at a Solution

I don't know how any equivalences for a = (b mod m), is there a way to get b from a = (b mod m)?

I had a + c = (b mod m) + d(mod m) but I'm not sure where to go from there