# Modulus and argument

## Homework Statement

So I'm trying to find the modulus and argument of
cosh(iπ)

## The Attempt at a Solution

so far coshπi = ½(e+e-iπ) Im now a bit stuck as what to do as i have two terms in the form eix and I'm not sure hw to combine them to get the argument?

Samy_A
Homework Helper

## Homework Statement

So I'm trying to find the modulus and argument of
cosh(iπ)

## The Attempt at a Solution

so far coshπi = ½(e+e-iπ) Im now a bit stuck as what to do as i have two terms in the form eix and I'm not sure hw to combine them to get the argument?
What is the value of e?

ah is it -1? in that case you'd have ½(-1-1) = -1. so it would just have radius of -1 modulus of π?

Samy_A
Homework Helper
ah is it -1? in that case you'd have ½(-1-1) = -1. so it would just have radius of -1 modulus of π?
cosh(iπ) is indeed equal to -1.

But what are the modulus and the argument? Remember that the modulus is always 0 or positive, never negative.

so modulus of 1 and argument of pi?

Samy_A