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Modulus and argument

  1. May 16, 2016 #1
    1. The problem statement, all variables and given/known data
    So I'm trying to find the modulus and argument of
    cosh(iπ)

    2. Relevant equations


    3. The attempt at a solution
    so far coshπi = ½(e+e-iπ) Im now a bit stuck as what to do as i have two terms in the form eix and I'm not sure hw to combine them to get the argument?
     
  2. jcsd
  3. May 16, 2016 #2

    Samy_A

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    What is the value of e?
     
  4. May 16, 2016 #3
    ah is it -1? in that case you'd have ½(-1-1) = -1. so it would just have radius of -1 modulus of π?
     
  5. May 16, 2016 #4

    Samy_A

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    cosh(iπ) is indeed equal to -1.

    But what are the modulus and the argument? Remember that the modulus is always 0 or positive, never negative.
     
  6. May 16, 2016 #5
    so modulus of 1 and argument of pi?
     
  7. May 16, 2016 #6

    Samy_A

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    Correct.
     
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