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Modulus and argument

  • Thread starter struggles
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  • #1
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Homework Statement


So I'm trying to find the modulus and argument of
cosh(iπ)

Homework Equations




The Attempt at a Solution


so far coshπi = ½(e+e-iπ) Im now a bit stuck as what to do as i have two terms in the form eix and I'm not sure hw to combine them to get the argument?
 

Answers and Replies

  • #2
Samy_A
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Homework Helper
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510

Homework Statement


So I'm trying to find the modulus and argument of
cosh(iπ)

Homework Equations




The Attempt at a Solution


so far coshπi = ½(e+e-iπ) Im now a bit stuck as what to do as i have two terms in the form eix and I'm not sure hw to combine them to get the argument?
What is the value of e?
 
  • #3
50
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ah is it -1? in that case you'd have ½(-1-1) = -1. so it would just have radius of -1 modulus of π?
 
  • #4
Samy_A
Science Advisor
Homework Helper
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510
ah is it -1? in that case you'd have ½(-1-1) = -1. so it would just have radius of -1 modulus of π?
cosh(iπ) is indeed equal to -1.

But what are the modulus and the argument? Remember that the modulus is always 0 or positive, never negative.
 
  • #5
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so modulus of 1 and argument of pi?
 
  • #6
Samy_A
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Homework Helper
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