- #1

nyrychvantel

- 14

- 0

since [tex]|x - 2| \ge 0[/tex], and for [tex]x|x - 2| \ge 1[/tex],

so [tex]x > 0[/tex]

Since [tex]x > 0[/tex], can I multiply the x inside to make it [tex]|{x^2} - 2x| \ge 1[/tex] ??

Or can you teach me your method of solving this question?

Thanks.