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Modulus inequality question

  1. May 10, 2009 #1
    For [tex]x|x - 2| \ge 1[/tex],

    since [tex]|x - 2| \ge 0[/tex], and for [tex]x|x - 2| \ge 1[/tex],
    so [tex]x > 0[/tex]

    Since [tex]x > 0[/tex], can I multiply the x inside to make it [tex]|{x^2} - 2x| \ge 1[/tex] ??


    Or can you teach me your method of solving this question?
    Thanks.
     
  2. jcsd
  3. May 10, 2009 #2
    modulus function questions are usually solved by taking cases.

    x > 2 and x < 2

    Take the value of the mod according to the two cases and solve it.. After you solve the inequality for one case, you will get a bound for x. Don't forget to put this together with x > 2 to get the actual bound for x...

    Accordingly do the next one
     
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