Modulus inequality question

  • #1
For [tex]x|x - 2| \ge 1[/tex],

since [tex]|x - 2| \ge 0[/tex], and for [tex]x|x - 2| \ge 1[/tex],
so [tex]x > 0[/tex]

Since [tex]x > 0[/tex], can I multiply the x inside to make it [tex]|{x^2} - 2x| \ge 1[/tex] ??


Or can you teach me your method of solving this question?
Thanks.
 

Answers and Replies

  • #2
311
1
modulus function questions are usually solved by taking cases.

x > 2 and x < 2

Take the value of the mod according to the two cases and solve it.. After you solve the inequality for one case, you will get a bound for x. Don't forget to put this together with x > 2 to get the actual bound for x...

Accordingly do the next one
 

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