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Homework Help: Mol fraction as a concentration?

  1. Mar 15, 2009 #1


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    1. The problem statement, all variables and given/known data

    2 solutions of C12H22O11 are mixed. Solution A is .150M with density of 1.05 g/mL. Solution B is 10%
    C12H22O11 by mass with density of 1.03g/mL. 100 mL of solution A is mixed with 100g of B. What is the mole fraction of C12H22O11 in the mixed solution?

    2. Relevant equations

    mole fraction = (mol of A + mol of B)/ total mols and also (volume of A + volume of B)/total Volume

    3. The attempt at a solution
    i tried converting both solutions into volumes and using the mole fraction formula regarding volumes to calculate mol fraction. but i doubt i got it right...

    for volume of solution A : .100L (.150mol/L)(342.99g/mol)(1 mL/1.05g) = 4.899 mL
    for B: 10g(1mL/1.03g) = 9.708737

    mol fraction = 4.899/14.60 = .335
  2. jcsd
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